Optimal. Leaf size=49 \[ \frac{1}{4} (1-x)^{3/2} x (x+1)^{3/2}+\frac{3}{8} \sqrt{1-x} x \sqrt{x+1}+\frac{3}{8} \sin ^{-1}(x) \]
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Rubi [A] time = 0.0066708, antiderivative size = 49, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.176, Rules used = {38, 41, 216} \[ \frac{1}{4} (1-x)^{3/2} x (x+1)^{3/2}+\frac{3}{8} \sqrt{1-x} x \sqrt{x+1}+\frac{3}{8} \sin ^{-1}(x) \]
Antiderivative was successfully verified.
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Rule 38
Rule 41
Rule 216
Rubi steps
\begin{align*} \int (1-x)^{3/2} (1+x)^{3/2} \, dx &=\frac{1}{4} (1-x)^{3/2} x (1+x)^{3/2}+\frac{3}{4} \int \sqrt{1-x} \sqrt{1+x} \, dx\\ &=\frac{3}{8} \sqrt{1-x} x \sqrt{1+x}+\frac{1}{4} (1-x)^{3/2} x (1+x)^{3/2}+\frac{3}{8} \int \frac{1}{\sqrt{1-x} \sqrt{1+x}} \, dx\\ &=\frac{3}{8} \sqrt{1-x} x \sqrt{1+x}+\frac{1}{4} (1-x)^{3/2} x (1+x)^{3/2}+\frac{3}{8} \int \frac{1}{\sqrt{1-x^2}} \, dx\\ &=\frac{3}{8} \sqrt{1-x} x \sqrt{1+x}+\frac{1}{4} (1-x)^{3/2} x (1+x)^{3/2}+\frac{3}{8} \sin ^{-1}(x)\\ \end{align*}
Mathematica [A] time = 0.0109164, size = 29, normalized size = 0.59 \[ \frac{1}{8} \left (x \sqrt{1-x^2} \left (5-2 x^2\right )+3 \sin ^{-1}(x)\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.004, size = 85, normalized size = 1.7 \begin{align*}{\frac{1}{4} \left ( 1-x \right ) ^{{\frac{3}{2}}} \left ( 1+x \right ) ^{{\frac{5}{2}}}}+{\frac{1}{4}\sqrt{1-x} \left ( 1+x \right ) ^{{\frac{5}{2}}}}-{\frac{1}{8}\sqrt{1-x} \left ( 1+x \right ) ^{{\frac{3}{2}}}}-{\frac{3}{8}\sqrt{1-x}\sqrt{1+x}}+{\frac{3\,\arcsin \left ( x \right ) }{8}\sqrt{ \left ( 1+x \right ) \left ( 1-x \right ) }{\frac{1}{\sqrt{1-x}}}{\frac{1}{\sqrt{1+x}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.52964, size = 39, normalized size = 0.8 \begin{align*} \frac{1}{4} \,{\left (-x^{2} + 1\right )}^{\frac{3}{2}} x + \frac{3}{8} \, \sqrt{-x^{2} + 1} x + \frac{3}{8} \, \arcsin \left (x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.55559, size = 124, normalized size = 2.53 \begin{align*} -\frac{1}{8} \,{\left (2 \, x^{3} - 5 \, x\right )} \sqrt{x + 1} \sqrt{-x + 1} - \frac{3}{4} \, \arctan \left (\frac{\sqrt{x + 1} \sqrt{-x + 1} - 1}{x}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 9.93612, size = 214, normalized size = 4.37 \begin{align*} \begin{cases} - \frac{3 i \operatorname{acosh}{\left (\frac{\sqrt{2} \sqrt{x + 1}}{2} \right )}}{4} - \frac{i \left (x + 1\right )^{\frac{9}{2}}}{4 \sqrt{x - 1}} + \frac{5 i \left (x + 1\right )^{\frac{7}{2}}}{4 \sqrt{x - 1}} - \frac{13 i \left (x + 1\right )^{\frac{5}{2}}}{8 \sqrt{x - 1}} - \frac{i \left (x + 1\right )^{\frac{3}{2}}}{8 \sqrt{x - 1}} + \frac{3 i \sqrt{x + 1}}{4 \sqrt{x - 1}} & \text{for}\: \frac{\left |{x + 1}\right |}{2} > 1 \\\frac{3 \operatorname{asin}{\left (\frac{\sqrt{2} \sqrt{x + 1}}{2} \right )}}{4} + \frac{\left (x + 1\right )^{\frac{9}{2}}}{4 \sqrt{1 - x}} - \frac{5 \left (x + 1\right )^{\frac{7}{2}}}{4 \sqrt{1 - x}} + \frac{13 \left (x + 1\right )^{\frac{5}{2}}}{8 \sqrt{1 - x}} + \frac{\left (x + 1\right )^{\frac{3}{2}}}{8 \sqrt{1 - x}} - \frac{3 \sqrt{x + 1}}{4 \sqrt{1 - x}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.09649, size = 80, normalized size = 1.63 \begin{align*} -\frac{1}{8} \,{\left ({\left (2 \,{\left (x + 1\right )}{\left (x - 2\right )} + 5\right )}{\left (x + 1\right )} - 1\right )} \sqrt{x + 1} \sqrt{-x + 1} + \frac{1}{2} \, \sqrt{x + 1} x \sqrt{-x + 1} + \frac{3}{4} \, \arcsin \left (\frac{1}{2} \, \sqrt{2} \sqrt{x + 1}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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